WebApr 9, 2010 · 41 Answers Sorted by: 1 2 Next 289 This should work: unsigned char reverse (unsigned char b) { b = (b & 0xF0) >> 4 (b & 0x0F) << 4; b = (b & 0xCC) >> 2 (b & 0x33) << 2; b = (b & 0xAA) >> 1 (b & 0x55) << 1; return b; } First the left four bits are swapped with the right four bits. WebApr 12, 2024 · Here first we will convert the number into binary form in a reverse way and every bit of binary number gets converted into decimal form and added to the previous one. For input (5)10 binary form is …
bitwise operators - how to use inverse in C - Stack Overflow
WebMar 25, 2015 · public ulong Bit (ulong x, int n) { return (x & (1 << n)) >> n; } public ulong ReverseBits (ulong x) { ulong result = 0; for (int i = 0; i < 64; i++) result = result (x.Bit (64 - i) << i); return result; } Share Improve this answer Follow answered Mar 25, 2015 at 17:53 MariusUt 752 4 15 Add a comment 0 WebThe algorithms you are currently using reverse the bits in the whole integer (i.e. 32 bits for an int and 64 bits for a long), whereas what you really want is to reverse only the first k bits (where n = 2^k for the bit-reversal permutation).. A simple solution would be to use strings: int x = 6; int k = 3; // Binary representation of x of length k string binaryString = … is cleaning services taxable in michigan
Bitwise and shift operators (C# reference)
WebAug 23, 2024 · Given a string, write a function that returns toggle case of a string using the bitwise operators in place. In ASCII codes, character ‘A’ is integer 65 = (0100 0001)2, while character ‘a’ is integer 97 = (0110 0001)2. Similarly, character ‘D’ is integer 68 = (0100 0100)2, while character ‘d’ is integer 100 = (0110 0100)2. WebMar 8, 2013 · Reverse the order of the bits in the binary number (also change the position of the first 0 (positive sign)): 0000000100010110 -> 0110100010000000. Take the first bit (of 0110100010000000): 0. 0 * 2 0 is 0, so write 0 Take the next bit: 1 1 * 2 1 is 2, so write 2 Take the next bit: 1 1 * 2 2 is 4, so write 4 Take the next bit: 0 WebFeb 5, 2012 · You could reverse the bits like you output them, and instead store them in another integer, and do it again : for (i = 0; i < (sizeof (unsigned int) * CHAR_BIT); i++) { new_int = (original_int & 1); original_int = original_int >> 1; new_int = new_int << 1; } Or you could just do the opposite, shift your mask : rv boondocking quartzsite az